Q. Arrange $NH_{4}^{+},H_{2}O,\ H_{3}O^{+},HF\ and\ OH^{-}$ in increasing order of acidic nature

A) $H_{3}O^{+} < NH_{4}^{+} < HF < OH^{-} < H_{2}O$
B) $NH_{4}^{+} < HF < H_{3}O^{+} < H_{2}O < OH^{-}$
C) $OH^{-} < H_{2}O < NH_{4}^{+} < HF < H_{3}O^{+}$
D) $H_{3}O^{+} > HF > H_{2}O > NH_{4}^{+} > OH^{-}$
Explanation

(c)
Among the given species, correct order of increasing acidic, strength is
$OH^{-} < H_{2}O < NH_{4}^{+} < HF < H_{3}O^{+}$
$OH^{-}$ is a basic (i.e., it tends to gain a proton) and hence is least acidic. $H_{2}O$ is neutral species. $H_{3}O^{+}$is most acidic as it readily lose proton.

Dr. Abubacker
Reviewed by Dr. Abubacker

Physics Educator & NEET/JEE Specialist

Ph.D. in Physics with 19+ years of teaching experience.

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