Q. If solubility of calcium hydroxide is $\sqrt{3}$, then its solubility product will be
A) $27$
B) $3$
C) $9$
D) $12\sqrt{3}$
Explanation
(d)
$Ca(OH)_{2} \rightleftharpoons Ca^{2 +} + 2OH^{-}$
$s$ $2s$
$K_{sp} = \lbrack S\rbrack\lbrack 2S\rbrack^{2}$ (where $S$=solubility)
$K_{sp} = 4S^{3}$
$K_{sp} = 4.\left( \sqrt{3} \right)^{3}$
$\ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ = 12\sqrt{3}$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.