Q. What is the effect of increasing pressure on the dissociation of $PCl_{5}$ according to the equation? $PCl_{5}(g) \rightleftharpoons PCl_{3}(g) + Cl_{2}(g)$
A) Dissociation decreases
B) Dissociation increases
C) Dissociation does not change
D) None of the above
Explanation
(a)
According to Le-chatelier principle the reactions in which number of moles are increasing in forward reaction are favoured at low pressure or high volume.
$PCl_{5}(g) \rightleftharpoons PCl_{3}(g) + Cl_{2}(g)$
$\because$ Number of moles are increasing in the forward reaction in above reaction.
$\because$ Reaction is favoured at low pressure.
$\because$ At high pressure, rate of dissociation of $PCl_{5}$ decreases.
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.