(b) $N_{2}(g) + 3H_{2}(g) \rightleftharpoons 2NH_{3}(g)$ $\mathrm{\Delta}n = n_{p} - n_{r}$ $= 2 - 4$ $= - 2$ $\therefore$ $K_{p} = K_{c}(RT)^{- 2}$ or $K_{p} = \frac{K_{c}}{(RT)^{2}}$ $K_{p} < K_{c}$
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.