Ionisation constant of $CH_{3}COOH$ is $1.7 imes 10^{- 5}$ and $\lbrack H^{+} brack$ ions is $3.4 imes 10^{- 4}$. Then, initial concentration of $CH_{3}COOH$ molecules is

Question

Ionisation constant of $CH_{3}COOH$ is $1.7 	imes 10^{- 5}$ and $\lbrack H^{+}brack$ ions is $3.4 	imes 10^{- 4}$. Then, initial concentration of $CH_{3}COOH$ molecules is

Dr. Abubacker · Accepted Answer

(a)
$\left\lbrack H^{+} ightbrack = \sqrt{K_{a} \bullet C}$
Where, $C =$initial concentration of the weak acid
$C = \frac{\left\lbrack H^{+} ightbrack^{2}}{K_{a}}$
$= \frac{\left( 3.4 	imes 10^{- 4} ight)^{2}}{1.7 	imes 10^{- 5}}$
$C = 6.8 	imes 10^{- 3}$ M

Q. Ionisation constant of $CH_{3}COOH$ is $1.7 \times 10^{- 5}$ and $\lbrack H^{+}\rbrack$ ions is $3.4 \times 10^{- 4}$. Then, initial concentration of $CH_{3}COOH$ molecules is

Explanation

Reviewed by Dr. Abubacker

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