Q. In which of the following reactions is $K_{p} < K_{c}$?
A) $I_{2}(g) \rightleftharpoons 2I(g)$
B) $2BrCl(g) \rightleftharpoons Cl_{2}(g) + Br_{2}(g)$
C) $CO(g) + 3H_{2}(g) \rightleftharpoons CH_{4}(g) + H_{2}O(g)$
D) All of the above
Explanation
(c)
$I_{2}(g) \rightleftharpoons 2I(g)$
$\mathrm{\Delta}n = n_{p} - n_{r}$
$= 2 - 1 = 1$
$K_{p} = K_{c}(RT)$
$2BrCl(g) \rightleftharpoons Cl_{2}(g) + Br_{2}(g)\$
$\mathrm{\Delta}n = 0$
$K_{p} = K_{c}(RT)^{0}$
$K_{p} = K_{c}$
$CO(g) + 3H_{2}(g) \rightleftharpoons CH_{4}(g) + H_{2}O(g)$
$\mathrm{\Delta}n = 2 - 4 = - 2$
$K_{p} = K_{c}(RT)^{- 2}$
$K_{p} < K_{c}$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.