Q. In the following reaction, $AgCl + KI \rightleftharpoons KCl + AgI$ as KI is added, the equilibrium is shifted towards right giving more $AgI$ precipitate. because
A) Both $AgCl\ and\ AgI$ are sparingly soluble
B) The $K_{sp}\ of\ AgI\ is\ lower\ than\ K_{sp}of\ AgCl$
C) The $K_{sp}of\ AgI\ is\ higher\ than\ K_{sp}of\ AgCl$
D) Both $AgCl\ and\ AgI$ have same solubility product
Explanation
(b)
The salt with lower solubility product ($AgI$) will precipitate first from the solution by adding KI.
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.