Q. For anionic hydrolysis, pH is given by
A) $pH = \frac{1}{2}pK_{w} - \frac{1}{2}pK_{b} - \frac{1}{2}\log C$
B) $pH = \frac{1}{2}pK_{w} + \frac{1}{2}pK_{a} - \frac{1}{2}pK_{b}$
C) $pH = \frac{1}{2}pK_{w} + \frac{1}{2}pK_{a} + \frac{1}{2}\log C$
D) $pH = - \frac{1}{2}(pK_{w} - pK_{a} - pK_{b})$
Explanation
The correct answer is Option C: $pH = \frac{1}{2}pK_{w} + \frac{1}{2}pK_{a} + \frac{1}{2}\log C$.
A detailed explanation for this question is being prepared.
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.