5 moles of $SO_{2}$ and 5 moles of $O_{2}$ are allowed to react. At equilibrium, it was found that 60% of $SO_{2}$ is used up. If the partial pressure of the equilibrium mixture is one atmosphere, the partial pressure of $O_{2}$ is

Question

Dr. Abubacker · Accepted Answer

(d)
$\ 2SO_{2}(g)\ \ \  + \ {\ \ O}_{2}(g)\ \ \ \ \  ightleftharpoons \ \ \ 2SO_{3}(g)$
Initial 5 5 0
At equilibrium (5-3) (5-1.5) 3
=2 =3.5
$	herefore pO_{2} = \frac{3.5 	imes 1}{8.5} = 0.41$atm

Q. 5 moles of $SO_{2}$ and 5 moles of $O_{2}$ are allowed to react. At equilibrium, it was found that 60% of $SO_{2}$ is used up. If the partial pressure of the equilibrium mixture is one atmosphere, the partial pressure of $O_{2}$ is

Explanation

Reviewed by Dr. Abubacker

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