(a)
$H_{2}\ \ \ \ \ \ \ \ \ \ \ I_{2}\ \ \ \ \ \rightleftharpoons \ \ \ \ \ \ 2HI$
Initially 1 mol 2 mol 2 mol
At equili 0.2 mol 2-0.8 2 0.8
1.2 mol 1.6 mol
Amount of $H_{2}\left( and\ hence\ I_{2} \right)\$consumed
$1 - 0.2\ \ \ \ \ \ \ \ \ 0.8$