Q. For a reaction if $K_{p} > K_{c}$ the forward reaction is favoured by

A) Low pressure
B) High pressure
C) High temperature
D) Low temperature
Explanation

(a)
For the reaction, we know that
$K_{p} = K_{c}(RT)^{\mathrm{\Delta}n_{g\ }}$
where, $\mathrm{\Delta}n_{g} =$ Number of gaseous moles of product – Number of gaseous moles of reactant
Hence, if $K_{p} > K_{c}$, then $\mathrm{\Delta}n$ must be positive.
It means that there is a decrease in volume of reaction, hence low pressure will favour the forward reaction.

Dr. Abubacker
Reviewed by Dr. Abubacker

Physics Educator & NEET/JEE Specialist

Ph.D. in Physics with 19+ years of teaching experience.

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