Q. A weak monobasic acid is 1% ionised in 0.1 M solution at 25$℃$. The percentage of ionisation in its 0.025 M solution is
A) 1
B) 2
C) 3
D) 4
Explanation
(b)
$C_{1}\alpha_{1}^{2} = C_{2}\alpha_{2}^{2}$
$0.1 \times 1^{2} = 0.025 \times \alpha_{2}^{2}$
$\alpha_{2}^{2} = 4$
$\alpha = 2$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.