Q. The solubility product of $As_{2}S_{3}\ is\ 2.8 \times 10^{- 72}$. What is the solubility of $As_{2}S_{3}$?

A) $1.92 \times 10^{- 15}$ mol/L
B) $1.72 \times 10^{- 15}$ mol/L
C) $2.3 \times 10^{- 16}$ mol/L
D) $1.65 \times 10^{- 36}$ mol/L
Explanation

(a)
$As_{2}S_{3} \rightleftharpoons 2{As}^{3 +} + 3S^{2 -}$
5 mol/L $2s$ $3s$
$K_{sp} = \left\lbrack {As}^{3 +} \right\rbrack^{2}\left\lbrack S^{2 -} \right\rbrack^{3}$
$= (2s)^{2}(3s)^{3}$
$\ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ = 108s^{5}$
$\therefore$ $s = \sqrt[5]{\frac{K_{sp}}{108}}\ \ \ \ or\ \ \ \left( \frac{K_{sp}}{108} \right)^{\frac{1}{5}}$
$= \sqrt[5]{\frac{2.8 \times 10^{- 72}}{108}}$
$= \sqrt[5]{25.93 \times 10^{- 75}}$
$= 1.92 \times 10^{- 15}$ mol/L

Dr. Abubacker
Reviewed by Dr. Abubacker

Physics Educator & NEET/JEE Specialist

Ph.D. in Physics with 19+ years of teaching experience.

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