Q. Which is a Lewis base $I_{2} + I^{-} \rightarrow I_{3}^{-}\ ?$
A) $I_{2}$
B) $I_{3}^{-}$
C) $I^{-}$
D) None of these
Explanation
(c)
Electron donors are Lewis base.
In the reaction $I_{2} + I^{-} \rightarrow I_{3}^{-},I^{-}$ donates a pair of electron and $I_{2}$ accepts it to form $I_{3}^{-}$.
$\therefore\ \ \ 1^{-}$ is Lewis base.
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.