Q. What is the effect of increasing pressure on the dissociation of $PCl_{5}$ according to the equation $PCl_{5}(g) \rightleftharpoons {PCl}_{3}(g) + {Cl}_{2}(g) - x\ cal$?
A) Dissociation decreases
B) Dissociation increases
C) Dissociation does not change
D) None of the above
Explanation
(a)
$PCl_{5}(g) \rightleftharpoons {PCl}_{3}(g) + {Cl}_{2}(g)$
For this reaction, $\mathrm{\Delta}n_{g} = 2 - 1 = 1$
Value of $\mathrm{\Delta}n_{g}$ is positive, so the dissociation of $PCl_{5}$ increases by decrease in pressure and by increase in pressure, the dissociation of $PCl_{5}$ decreases
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.