Q. The pH of an aqueous solution containing [$H^{+}$] concentration =$3.0 \times 10^{- 3}$ M. The pH of the solution is
A) 2.523
B) 3.0
C) 2.471
D) None of these
Explanation
(a)
$pH = - \log{\lbrack H^{+}\rbrack}$
$= - \log{(3 \times 10^{- 3})}$
$= 3 - \log 3$
$= 3 - 0.4771$
$\ = 2.5229$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.