Q. The pH of a buffer solution containing equal molal concentration of a weak base and its chloride ($K_{b}\ for\ \ weak\ base = 2 \times 10^{- 5}$) is

A) $5$
B) $9$
C) $4.7$
D) $9.3$
Explanation

(d)
For basic buffer,
$pOH = pK_{b} + \log\frac{\lbrack salt\rbrack}{\lbrack base\rbrack}$
Given, [salt]=[base]=1
$K_{b} = 2 \times 10^{- 5}$
$\therefore$ $pOH = pK_{b} = - \log{(2 \times 10^{- 5})}$
$= 5 - \log 2$
$\ = 5 - 0.30 = 4.70$
$pH = 14 - pOH$
$= 14 - 4.70 = 9.30$

Dr. Abubacker
Reviewed by Dr. Abubacker

Physics Educator & NEET/JEE Specialist

Ph.D. in Physics with 19+ years of teaching experience.

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