Q. The expression for the solubility product of $Ag_{2}CO_{3}$ will be
A) $K_{sp}\ \ \ s^{2}$
B) $K_{sp}\ \ \ \ 4s^{3}$
C) $K_{sp}\ \ \ \ 27s^{4}$
D) $K_{sp}\ \ \ s$
Explanation
(b)
$Ag_{2}CO_{3}(s) \rightleftharpoons 2{Ag}^{+} + {CO}_{3}^{2 -}$
$s$ $2s$ $s$
$K_{sp} = \left\lbrack {Ag}^{+} \right\rbrack^{2}\left\lbrack {CO}_{3}^{2 -} \right\rbrack = (2s)^{2}.s$
$\therefore$ $K_{sp} = 4s^{3}$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.