Phosphorus pentachloride dissociates as follows, in a closed reaction vessel, $PCl_{5}(g) \rightleftharpoons PCl_{3}(g) + Cl_{2}(g)$ If total pressure at equilibrium of the reaction mixture is $p$ and degree of dissociation of $PCl_{5}\ is\ x$, the partial pressure of $PCl_{3}$ will be

Question

Dr. Abubacker · Accepted Answer

(a)
$PCl_{5}(g) ightleftharpoons PCl_{3}(g) + Cl_{2}(g)$
$(1 - x)$ $x$ $x$
Total number of moles at equilibrium
$= (1 - x) + x + x$
$= 1 + x$
$p_{PCl_{3}} = \left( \frac{x}{1 + x} ight) 	imes p$

Q. Phosphorus pentachloride dissociates as follows, in a closed reaction vessel, $PCl_{5}(g) \rightleftharpoons PCl_{3}(g) + Cl_{2}(g)$ If total pressure at equilibrium of the reaction mixture is $p$ and degree of dissociation of $PCl_{5}\ is\ x$, the partial pressure of $PCl_{3}$ will be

Explanation

Reviewed by Dr. Abubacker

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