The equilibrium constant for the reaction $SO_{3}(g) ightleftharpoons SO_{2}(g) + \frac{1}{2}O_{2}(g)$ is $K_{c} = 4.9 imes 10^{- 2}$. The value of $K_{c}$ for the reaction $2SO_{2}(g) + O_{2}(g) ightleftharpoons 2SO_{3}(g)$ will be

Question

The equilibrium constant for the reaction $SO_{3}(g) ightleftharpoons SO_{2}(g) + \frac{1}{2}O_{2}(g)$ is $K_{c} = 4.9 	imes 10^{- 2}$. The value of $K_{c}$ for the reaction $2SO_{2}(g) + O_{2}(g) ightleftharpoons 2SO_{3}(g)$ will be

Dr. Abubacker · Accepted Answer

(a)
Equilibrium constant for the reaction,
$SO_{2}(g) + \frac{1}{2}O_{2} ightleftharpoons SO_{3}(g)$
$K_{c} = \frac{1}{4.9 	imes 10^{- 2}}$
and for $2SO_{2} + O_{2} ightleftharpoons 2SO_{3}(g)\$
$K_{c} = \left( \frac{1}{4.9 	imes 10^{- 2}} ight)^{2}$
$= \frac{10^{4}}{(4.9)^{2}} = 416.49$

Q. The equilibrium constant for the reaction $SO_{3}(g) \rightleftharpoons SO_{2}(g) + \frac{1}{2}O_{2}(g)$ is $K_{c} = 4.9 \times 10^{- 2}$. The value of $K_{c}$ for the reaction $2SO_{2}(g) + O_{2}(g) \rightleftharpoons 2SO_{3}(g)$ will be

Explanation

Reviewed by Dr. Abubacker

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