Q. In the reaction, $3A + 2B \rightarrow 2C,$ the equilibrium constant $K_{c}$ is given by
A) $\frac{\lbrack 3A\rbrack \times \lbrack 2B\rbrack}{\lbrack C\rbrack}$
B) $\frac{\lbrack A\rbrack^{3} \times \lbrack B\rbrack}{\lbrack C\rbrack}$
C) $\frac{\lbrack C\rbrack^{2}}{\lbrack A\rbrack^{3} \times \lbrack B\rbrack^{2}}$
D) $\frac{\lbrack C\rbrack}{\lbrack 3A\rbrack\lbrack 2B\rbrack}$
Explanation
(c)
$3A + 2B \rightarrow 2C$
$K_{c} = \frac{concentration\ of\ products}{concnetration\ of\ reactants}$
$= \frac{\lbrack C\rbrack^{2}}{\lbrack A\rbrack^{3} \times \lbrack B\rbrack^{2}}$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.