(d)
$2SO_{2}(g) + O_{2}(g) \rightleftharpoons 2{SO}_{3}(g)$
For $1\ dm^{3},\ \ R = k\left\lbrack SO_{2} \right\rbrack^{2}\lbrack O_{2}\rbrack$
$R = k\left\lbrack \frac{1}{T} \right\rbrack^{2}\left\lbrack \frac{1}{1} \right\rbrack = 1$
For $2\ dm^{3},\ \ R = k\left\lbrack \frac{1}{2} \right\rbrack^{2}\left\lbrack \frac{1}{2} \right\rbrack = \frac{1}{8}$
So, the ratio is 8 : 1