Q. In Haber process, 30 L of dihydrogen and 30 L of dinitrogen were taken for reaction which yielded only 50% of the expected product. What will be the composition of gaseous mixture under the aforesaid condition in the end?
A) $10\ L\ NH_{3},\ 25\ L\ N_{2},\ 15\ L\ H_{2}$
B) $20\ L\ NH_{3},\ 20\ L\ N_{2},\ 20\ L\ H_{2}$
C) $20\ L\ NH_{3},\ 25\ L\ N_{2},\ 15\ L\ H_{2}$
D) $20\ L\ NH_{3},\ 10\ L\ N_{2},\ 30\ L\ H_{2}$
Explanation
(a)
${\ N}_{2} + \ \ \ \ \ 3H_{2} \rightleftharpoons \ 2{NH}_{3}$
$\ \ \ \ \ \ \ 30\ \ \ \ \ \ \ \ \ \ 30\ \ \ \ \ \ \ \ \ \ \ \ 0$ initially
$(30 - x)(30 - x)\ \ \ 2x$ at equilibrium
$2x = 10\ \ \therefore x = \frac{10}{2} = 5$
$N_{2} = 30 - 5 = 25\ L$
$H_{2} = 30 - 3 \times 5 = 15L$
$NH_{3} = 2 \times 5 = 10L$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.