Q. For the reaction, $2NO_{3}(g) \rightleftharpoons 2NO(g) + O_{2}(g)$ $(K_{c} = 1.8 \times 10^{- 6}\ at\ 184℃)$ $(R = 0.00831$ kJ/(mol K) When $K_{p}and\ K_{c}$ are compared at $184℃$, it is found that
A) Whether $K_{p}$ is greater than less than or equal to $K_{c}$depends upon the total gas pressure
B) $K_{p} = K_{c}$
C) $K_{p}$ is less than $K_{c}$
D) $K_{p}$ is greater than $K_{c}$
Explanation
(d)
$2NO_{3}(g) \rightleftharpoons 2NO(g) + O_{2}(g)$
$K_{c} = 1.8 \times 10^{- 6}\ at\ 184℃( = 457K)$
$R = 0.00831\ kJ\ mol^{- 1}K^{- 1}$
$K_{p} = K_{c}(RT)^{\mathrm{\Delta}n_{g}}$
Where,
$\mathrm{\Delta}n_{g} =$ (gaseous products – gaseous reactants)
=3-2=1
$\therefore$ $K_{p} = 1.8 \times 10^{- 6} \times 0.00831 \times 457$
$= 6.836 \times 10^{- 6} > 1.8 \times 10^{- 6}$
Thus, $K_{p} > K_{c}$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.