Q. The expression for the solubility product of $Al_{2}\left( SO_{4} \right)_{3}$ is

A) $K_{sp} = \lbrack{Al}^{3 +}\rbrack\ \lbrack SO_{4}^{2 -}\rbrack$
B) $K_{sp} = \left\lbrack {Al}^{3 +} \right\rbrack^{2}\left\lbrack SO_{4}^{2 -} \right\rbrack^{3}$
C) $K_{sp} = \left\lbrack {Al}^{3 +} \right\rbrack^{3}\left\lbrack SO_{4}^{2 -} \right\rbrack^{2}$
D) $K_{sp} = \left\lbrack {Al}^{3 +} \right\rbrack^{2}\left\lbrack SO_{4}^{2 -} \right\rbrack^{2}$
Explanation

(b)
$Al_{2}\left( SO_{4} \right)_{3} \rightleftharpoons 2Al^{3 +} + 3SO_{4}^{2 -}$
$K_{sp} = \lbrack{{Al}^{3 +}\rbrack}^{2}\left\lbrack SO_{4}^{2 -} \right\rbrack^{3}$

Dr. Abubacker
Reviewed by Dr. Abubacker

Physics Educator & NEET/JEE Specialist

Ph.D. in Physics with 19+ years of teaching experience.

Want more practice?
Practice Equilibrium MCQs