Q. The vapour density of $PCl_{5}$ is 104.16, but when heated at $230℃$. Its vapour density is reduced to 62. The percentage of dissociation of $PCl_{5}$ at this temperature will be
A) 6.8%
B) 68%
C) 46%
D) 64%
Explanation
(b)
$\alpha = \frac{D - d}{d} = \frac{104.16 - 62}{62}$
$= 0.68 = 68\%$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.