If in the reaction $N_{2}O_{4} \rightleftharpoons 2NO_{2}$, $x$ is that part of $N_{2}O_{4}$ which dissociates, then the number of molecules at equilibrium will be

Question

Dr. Abubacker · Accepted Answer

(c)
$N_{2}O_{4} \rightleftharpoons 2NO_{2}$
1 0 Before dissociation
$1 - x$ $2x$ After dissociation
Total number of moles at equilibrium
$= 1 - x + 2x = 1 + x$

Q. If in the reaction $N_{2}O_{4} \rightleftharpoons 2NO_{2}$, $x$ is that part of $N_{2}O_{4}$ which dissociates, then the number of molecules at equilibrium will be

Explanation

Reviewed by Dr. Abubacker

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