Q. For the reaction, $2NO_{2}(g) \rightleftharpoons 2NO(g) + O_{2}(g),\ K_{c} = 1.8 \times 10^{- 6}$at $185℃$. At $185℃$, the value of $K_{c}$ for the reaction, $NO(g) + \frac{1}{2}O_{2}(g) \rightleftharpoons {NO}_{2}(g)$ is
A) $0.9 \times 10^{6}$
B) $1.9 \times 10^{6}$
C) $7.5 \times 10^{2}$
D) $5.7 \times 10^{2}$
Explanation
(c)
Reaction is reverse and halved
$K = \sqrt{\frac{1}{1.8 \times 10^{- 6}}} = 7.5 \times 10^{2}$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.