Q.
A weak acid $HX$ has the dissociation constant $1 \times 10^{- 5}$ M. It forms a salt $NaX$ on reaction with alkali. The degree of hydrolysis of 0.1 M solution of Na$X$ is
A) 0.0001%
B) 0.01%
C) 0.1%
D) 0.15%
Explanation
(b)
$X^{-} + H_{2}O \rightleftharpoons HX + OH^{-}$
$K_{h} = \frac{10^{- 14}}{10^{- 5}}so,\ h = \sqrt{\frac{K_{h}}{C}} = \sqrt{\frac{10^{- 9}}{10^{- 1}}} = 10^{- 4}$
$= 100 \times 10^{- 4} = 10^{- 2}$
So, degree of hydrolysis is 0.01%
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.