(d)
$CaCO(s) \rightleftharpoons CaO(s) + CO_{2}(g)$
The equilibrium constant for this reaction is given by $K = \left\lbrack CO_{2} \right\rbrack($as$\ CaCO_{3}\$and$\ CaO\$are solid$)$.
Hence, to get more $CO_{2}$, we need to pump out continuously the $CO_{2}$ gas.