Q. In the equilibrium, $AB \rightleftharpoons A + B,$ if the equilibrium concentration of $A$ is doubled, the equilibrium concentration of $B$ would become
A) Half
B) Twice
C) $\frac{1}{4}th$
D) $\frac{1}{8}th$
Explanation
(a)
$AB \rightleftharpoons A + B$
$K = \frac{\lbrack A\rbrack\lbrack B\rbrack}{\lbrack AB\rbrack}$
If concentration of $A$ is doubled, the equilibrium concentration of $B$ becomes half
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.