Q. A saturated solution prepared by dissolved $CaF_{2}(s)$ in water, has $\left\lbrack Ca^{2 +} \right\rbrack = 3.3 \times 10^{- 4}$ M. What is the $K_{sp}$of $CaF_{2}$?

A) $1.44 \times 10^{- 10}$
B) $2.24 \times 10^{- 8}$
C) $1.58 \times 10^{- 8}$
D) $1.67 \times 10^{- 8}$
Explanation

(a)
$CaF_{2}(s) \rightleftharpoons {Ca}^{2 +}(aq) + 2F^{-}(aq)$
$\left\lbrack F^{-} \right\rbrack = 2\left\lbrack Ca^{2 +} \right\rbrack$
$= 2 \times 3.3 \times 10^{- 4}$
$= 6.6 \times 10^{- 4}$ M
$K_{sp} = \left\lbrack Ca^{2 +} \right\rbrack\left\lbrack F^{-} \right\rbrack^{2}$
$= \left( 3.3 \times 10^{- 4} \right)\left( 6.6 \times 10^{- 4} \right)^{2}$
$= 1.44 \times 10^{- 10}$

Dr. Abubacker
Reviewed by Dr. Abubacker

Physics Educator & NEET/JEE Specialist

Ph.D. in Physics with 19+ years of teaching experience.

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