In the following reaction $M^{x +} + {MnO}_{4}\ \ \ \ \ \ \ MO_{3} + {Mn}^{2 +} + \frac{1}{2}O_{2},$ If one mole of ${MnO}_{4}$ oxidises 2.5 moles of $M^{x +}$ then the value of $x$ is

Question

Dr. Abubacker · Accepted Answer

(b)
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$x + 2 = 5$
$	herefore$ $x = 5 - 2 = \  + 3\$

Q. In the following reaction $M^{x +} + {MnO}_{4}\ \ \ \ \ \ \ MO_{3} + {Mn}^{2 +} + \frac{1}{2}O_{2},$ If one mole of ${MnO}_{4}$ oxidises 2.5 moles of $M^{x +}$ then the value of $x$ is

Explanation

Reviewed by Dr. Abubacker

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