Q. Oxidation number of ‘N’ in $N_{3}H$(hydrazoic acid) is
A) $- \frac{1}{3}$
B) $+ 3$
C) 0
D) $- 3$
Explanation
(a)
$N_{3}H\ (hydrazoic\ acid)$
$+ 3(x) + 1 = 0$
$3x + 1 = 0$
$x = - \frac{1}{3}$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.