Q. The difference in the oxidation numbers of the two types of sulphur atoms in ${Na}_{2}S_{4}O_{6}$ is
A) 4
B) 5
C) 6
D) 7
Explanation
(b)
${Na}_{2}S_{4}O_{6}$ is salt of $H_{2}S_{4}O_{6}$ which has the following structure
[image:8_image4.emf]
$\Rightarrow \$Difference in oxidation number of two types of sulphur = 5 $\ \$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.