(d)
${NaNO}_{2}$ (Sodium nitrite) acts both as oxidising as well as reducing agent because in it N-atom is in +3 oxidation state (intermediate oxidation state).
Oxidising property
$2{NaNO}_{2} + 2KI + 2H_{2}{SO}_{4} \longrightarrow {Na}_{2}{SO}_{4} + K_{2}{SO}_{4} + 2NO + 2H_{2}O + I_{2}$
Reducing property
$H_{2}O_{2} + {NaNO}_{2} \longrightarrow {NaNO}_{3} + H_{2}O\$