Q. The oxidation number of Cr in ${CrO}_{5}$ is
A) +3
B) +5
C) +6
D) 0
Explanation
(c)
[image:8_image5.emf] $ie,$ it has four peroxide bonds each having an oxidation number of $- 1$ and one double bond in which oxidation number of O is $- 2$
Therefore, $x + 4 \times ( - 1) + 1 \times ( - 2) = 0$
$\therefore x = \ \times 6$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.