(d)
Permonosulphuric acid ($H_{2}{SO}_{5})\$has two oxygen atoms in peroxide linkage, hence,
$2( + 1) + x + 2( - 1) + 3( - 2) = 0\ \$
$2 + x - 2 - 6 = 0$
$\ \ \ \ \ \ \ \ x\$=+6$\ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \$