Q. The number of moles of ${KMnO}_{4}$ reduced by one mole of $KI$ in alkaline medium is
A) 1
B) 5
C) ½
D) 1/5
Explanation
(a)
In alkaline medium
_{+7 +6}
${KMnO}_{4} + {OH}^{-}\ \longrightarrow K_{2}{MnO}_{4}$
Change in oxidation number
= 7$- 6$
= 1
Hence, moles of KI = moles of ${KMnO}_{4}.$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.