Q. The oxidation number of Cr in $K_{2}{CrO}_{4}$ is
A) +3
B) $- 6$
C) $+ 6$
D) $- 3$
Explanation
(c)
Let the oxidation number of Cr in $K_{2}{CrO}_{4}$ is $x.$
$2( + 1) + x + 4( - 2) = 0$
$2 + x - 8 = 0$
$x = + 6$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.