Q. In the reaction, ${SO}_{2} + 2H_{2}S\ \rightarrow 3S + 2H_{2}O$ the substance that oxidizes is,
A) $H_{2}S$
B) ${SO}_{2}$
C) $S$
D) $H_{2}O$
Explanation
(a)
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The oxidation number of S increases from $- 2$ to 0 in elemental sulphur and hence, $H_{2}S$ gets oxidized
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.