The coefficients of $\ I^{-},\ {\ IO}_{3}^{-}\ and\ H^{+}$ in the redox reaction, $I^{-} + \ {IO}_{3}^{-} + H^{+} \rightarrow I_{2} + H_{2}O$ in the balanced form respectively are

Question

Dr. Abubacker · Accepted Answer

(a)
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On adding Eq. (i) and (ii), we get
$10I^{-} + 2{IO}_{3}^{-} \rightarrow 6I_{2}$
To balance O atom, add $6H_{2}O$ molecules on RHS and $12H^{+}$ on LHS, then
$10I^{-} + 2{IO}_{3}^{-} + 12H^{+} \rightarrow 6I_{2} + 6H_{2}O$
or$\ 5I^{-} + {IO}_{3}^{-} + 6H^{+} \rightarrow 3I_{2} + 3H_{2}O$

Q. The coefficients of $\ I^{-},\ {\ IO}_{3}^{-}\ and\ H^{+}$ in the redox reaction, $I^{-} + \ {IO}_{3}^{-} + H^{+} \rightarrow I_{2} + H_{2}O$ in the balanced form respectively are

Explanation

Reviewed by Dr. Abubacker

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