Q. The oxidation number of N and Cl in ${NOClO}_{4}$ respectively are
A) +2 and +7
B) +3 and +7
C) $- 3\$and +5
D) +2 and $- 7$
Explanation
(b)
Oxidation no. of N in ${NO}^{+}$ is
$(1 \times x) + 1 \times ( - 2) = + \ 1$
$\therefore\ x = + \ 3$
Oxidation no. of Cl in$\ {ClO}_{4}^{-}$ is
$(1 \times x) + \ 4 \times ( - 2) = - \ 1$
$x = + \ 7$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.