Q. The oxidation states of iodine in ${HIO}_{4},\ H_{3}{IO}_{5}$ and $H_{5}{IO}_{6}$ are respectively
A) +1,+3,+7
B) +7,+7,+3
C) +7,+7,+7
D) +7,+5,+3
Explanation
(c)
The oxidation state of iodine in $HIO_{4}\ is + 7$ as
$1 + x + 4( - 2) = 0$
$x = + 7$
The oxidation state of iodine in $H_{3}{IO}_{5}$ is +7 as
3$+ x + 5( - 2) = 0$
$x = + 7$
The oxidation state of iodine in $H_{5}IO_{6}$ is +7 as
5$+ x + 6( - 2) = 0$
$x = + 7$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.