Q. Oxidation state of sulphur in ${Na}_{2}S_{2}O_{3}$ and ${Na}_{2}S_{4}O_{6}$
A) 4 and 6
B) 3 and 5
C) 2 and 2.5
D) 6 and 6
Explanation
(c)
${Na}_{2}S_{2}O_{3},$
$2( + 1) + 2x + 3( - 2) = 0$
$2 + 2x - 6 = 0$
$x = + 2$
${Na}_{2}S_{4}O_{6}$
$2( + 1) + 4(x) + 6( - 2) = 0$
$2 + 4x - 12 = 0$
$4x = + 10$
$x = \ + 2.5$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.