${MnO}_{4}^{-}$ is a good oxidising agent in different medium changing to ${MnO}_{4}^{-}\ \longrightarrow {Mn}^{2 +}$ $\longrightarrow \ {MnO}_{4}^{2 -}$ $\longrightarrow {\ MnO}_{2}$ $\longrightarrow {Mn}_{2}O_{3}$ Changes in oxidation number respectively are

Question

Dr. Abubacker · Accepted Answer

(c)
${MnO}_{4}^{-} = Mn = + 7$
${MnO}_{4}^{2 -} = Mn = + 6$
${\ \ MnO}_{2} = Mn = + 4$
${Mn}_{2}O_{3} = Mn = + 3$
Hence, changes in oxidation number are 5,1,3,4.

Q. ${MnO}_{4}^{-}$ is a good oxidising agent in different medium changing to ${MnO}_{4}^{-}\ \longrightarrow {Mn}^{2 +}$ $\longrightarrow \ {MnO}_{4}^{2 -}$ $\longrightarrow {\ MnO}_{2}$ $\longrightarrow {Mn}_{2}O_{3}$ Changes in oxidation number respectively are

Explanation

Reviewed by Dr. Abubacker

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