Q. Oxidation number of nitrogen is highest in
A) $N_{3}H$
B) $N_{2}O_{4}$
C) ${NH}_{2}OH$
D) ${NH}_{3}$
Explanation
(b)
In $N_{3}H$
Oxidation number of N = $- \frac{1}{3}$
In $N_{2}O_{4}\ \ \ \ \ Oxidation\ number\ of\ N$ $= + 4$
In ${NH}_{2}OH\ Oxidation\ number\ of\ N = - 1$
In ${NH}_{3}\ \ \ \ \ \ \ Oxidation\ number\ of\ N$ =$- 3$
Hence, in $N_{2}O_{4}\$the oxidation number of nitrogen is highest.
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.