Q. What is the oxidation state of P in $Ba\left( H_{2}{PO}_{2} \right)_{2}?$
A) +1
B) +2
C) +3
D) $- 1$
Explanation
(a)
Let oxidation state of P in $Ba\left( H_{2}PO_{2} \right)_{2}\ is\ x,\ then$
$2( + 1) + 2\left\lbrack 2( + 1) + x + 2( - 2) \right\rbrack = 0$
$2 + 2(2 + x - 4) = 0$
$2 + 4 + 2x - 8 = 0$
$2 + 2x - 4 = 0$
$2x = 2$
$x = + 1$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.