Q. In the compounds ${KMnO}_{4}\ and\ K_{2}{Cr}_{2}O_{7},$ the highest oxidation state is of the element
A) Mn
B) K
C) O
D) Cr
Explanation
(a)
Mn has +7 oxidation state in ${KMnO}_{4}.$
$1 + x + 4( - 2) = 0$
$1 + x - 8 = 0$
$x = + 7\$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.