Q. The strength in volumes of a solution containing 30.36g/L of $H_{2}O_{2}$ is
A) 10 volume
B) 20 volume
C) 5 volume
D) None of these
Explanation
(a)
Strength of $H_{2}O_{2}$ in g/L $= \frac{68}{22.4} \times V$
Given strength of $H_{2}O_{2} = 30.36\ g/L$
Or $\ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ V = \frac{30.36\ \times \ 22.4}{68}$
$\ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ = 10\ volumes$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.